Random rndGen = new Random();
int[] player1 = { 0, 0, 0, 0, 0, 0 };
int[] player2 = { 0, 0, 0, 0, 0, 0 };
for (int i = 0; i < 5; i++)
{
   player1[rndGen.Next(0, 5)] += 1;
   player2[rndGen.Next(0, 5)] += 1;
}
//Let's assume in array entry 0 we store the value 6, in 1->5 etc.
int iWinner = 0; // if iWinner == 0 we have a draw
int iHowmany = 0; // here we store how many of a kind has won
for (int i = 0; i < 5; i++)
{
   if (player1[i] > player2[i] && player1[i] > iHowmany)
   {
      iWinner = 1;
      iHowmany = player1[i];
   }
   else if (player1[i] < player2[i] && player2[i] > iHowmany)
   {
      iWinner = 2;
      iHowmany = player2[i];
   }
}

// Look in iWinner who has won

Note that this doesn't hold into account that 2 pairs of 3 and 4 could be valued more than 1 pair of 5 Smiley

Good luck,
Peter