A moving question

Why can't container::value_type invoke a move like make_pair can ?

I'm using Visual Studio 2012

Code example

#include <iostream>
#include <unordered_map>
#include <utility> // move, make_pair
#include <algorithm> // swap

struct move_me {
    typedef move_me class_type;
    int *ptr_value;
    int moved;
    int copied;

    move_me() : ptr_value(nullptr), moved(), copied() {}
    explicit move_me(const int val) : ptr_value(new int(val)), moved(), copied() {
    }
    ~move_me() {
        if (ptr_value) {
            delete ptr_value;
        }
    }

    // Copy
    move_me(const move_me &other) :
        moved(other.moved), copied(other.copied + 1) {
            if (other.ptr_value) {
                ptr_value = new int(*other.ptr_value);
            } else {
                ptr_value = nullptr;
            }
    }
    move_me &operator=(const move_me &other) {
        move_me(other).swap(*this);
        return *this;
    }

    // Move
    move_me(move_me &&other) {
        ptr_value = other.ptr_value;
        other.ptr_value = nullptr;
        moved = other.moved + 1;
        copied = other.copied;
    }
    move_me &operator=(move_me &&other) {
        move_me(std::move(other)).swap(*this);
        return *this;
    }

    void print() const {
        using namespace std;
        if (ptr_value)
            cout << "ptr_value: " << *ptr_value << endl;
        else
            cout << "ptr_value: <nullptr>" << endl;
        cout << "moved: " << moved << endl;
        cout << "copied: " << copied << endl;
    }
    void swap(move_me& other) {
        std::swap(ptr_value, other.ptr_value);
        std::swap(moved, other.moved);
        std::swap(copied, other.copied);
    }

    size_t hash() const {
        return std::hash<int>()(*ptr_value);
    }
    bool operator==(const class_type& other) const { return *ptr_value == *other.ptr_value; }
    bool operator< (const class_type& other) const { return *ptr_value < *other.ptr_value; }
    bool operator<=(const class_type& other) const { return *ptr_value <= *other.ptr_value; }
};

struct hash_move_me {
    size_t operator()(const move_me& key_val) const {
        return key_val.hash();
    }
};

int main()
{
    using namespace std;

    typedef unordered_map<move_me, size_t, hash_move_me> m_type;
    m_type m;

    auto find_and_prt = [&](const int val) {
        m.find(move_me(val))->first.print();
        cout << endl;
    };

    // Normal way
    // Expect only moves
    m.insert(m_type::value_type(move_me(111), 123));
    find_and_prt(111);

    // Lets make it very clear for the compiler that we want a move here
    m.insert(move(m_type::value_type(move(move_me(222)), 123)));
    find_and_prt(222);

    // We're in luck, special case, standard container
    m.insert(make_pair(move_me(333), 123));
    find_and_prt(333);

    cout << "done" << endl << endl;
    return 0;
}

This function use forward:

Should it not use move instead?

I used forward in one of my classes, that also caused a copy so i switch to move which did the desired action.

Can somebody explain why the code doesn't do the right thing?

    template<class _Other1,
        class _Other2>
        pair(pair<_Other1, _Other2>&& _Right,
            typename enable_if<is_convertible<_Other1, _Ty1>::value
                && is_convertible<_Other2, _Ty2>::value,
                void>::type ** = 0)
        : first(_STD forward<_Other1>(_Right.first)),
            second(_STD forward<_Other2>(_Right.second))
        {    // construct from moved compatible pair
        }

Why showing the error in this code. Anyone can let me know.