Help with XPATH / XSLT

Posted By: VB Man | Sep 29th, 2008 @ 9:11 PM
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#Sep 29th, 2008 @ 9:11 PM
VB Man
VB Man
Year of the Linux MCE.
HI ALL. I have the following element:

<child firstname="smith" age="10" dayborn="19"/>

How can I extract the age of the child using XPath?

Much thanks.


#Sep 29th, 2008 @ 9:20 PM
Sven Groot
Sven Groot
My name has 9 letters. Coincidence? I think not...
If for example you want to select it by firstname:

//child[@firstname='smith']/@age

(Note that this searches all child elements in the document. You might want something more precise than using // at the start)
#Sep 29th, 2008 @ 9:33 PM
VB Man
VB Man
Year of the Linux MCE.
Hm I tried that but it's still not working.

<xsl:if test="//child[@firstname='smith']/@age &lt; 10">
<xsl:text>User under 10 years of age</xsl:text>
</xsl:if>

It's not showing User under 10 years of age but it is in the xml. Any suggestions?
#Sep 29th, 2008 @ 9:39 PM
Sven Groot
Sven Groot
My name has 9 letters. Coincidence? I think not...
Well, that's obviously not going to match the element from your original post since that child is 10, which is not less than 10.

A little more context would be nice, such as the entire XML document and style sheet.
#Sep 29th, 2008 @ 9:42 PM
VB Man
VB Man
Year of the Linux MCE.
Nevermind, I got it using &lt;= '10'. Thank you for your second post though, really helped me out. Big Smile
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