, Bass wrote


Can you point out a situation where type inference can't tell what a type would be, but a programmer can?

function  add(var1, var2) { return var1 + var2; }

alert(add(1, 2)); alert(add("1", "2"));

In this case, add will be implemented by a call, not by an ADD because two type inference passes will come back with different types.

If this was done via a C++ template the first time will be an ADD opcode for integer addition and the second one will be done by a call to a string concatenation routine.